Answer to Question #191695 in Civil and Environmental Engineering for John Prats

Question #191695

When a battery is connected to the plates of a 3.00-µF capacitor, it stores a charge of 27.0 µC. What is the voltage of the battery?


1
Expert's answer
2021-05-14T13:57:02-0400


Q=27"\\mu C" = "27 \\times 10^{-6} " C

C= -3.0 "\\mu F" = -3.0 "\\times 10^{-6}" F


V= voltage of the battery, C= system capacitance , Q= charge stored by the capacitor


"Q= CV "


" \n\n\n\n\n\n\n\nV=\\frac{Q}{C}= \\frac{27\\times 10^{-6} C}{3.0\\times 10^{-6}F}"


V=9.0V




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