Question #191084

A civil engineer takes a public ride going to his firm. The average time for his trip is 24 minutes, with a standard deviation of 3.80 minutes. If the office offers coffe from 8:50AM to 9:00AM, and he leaves his house at 8:35AM, what is the probability (in percent) that he misses coffee?

Expert's answer

Required Probability

P(X>25)=1-P(X<=25)

=1-P((X-mu)/sigma<=(25-24)/3.8)

=1-(P(Z)<=0.23)

=1-0.6026

=0.3974

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