Question #177610

Calculate the area bounded by y=x3

, x=0 and y=3.

Expert's answer

y=x3

, x=0 and y=3.

f(x)= x^{3 }and g(x) = 3

given that,

x=0

in order to find second interval, we have to find the point of intersection of y=x^{3} and y=3

Hence, 3=x^{3} therefore x=1.442

hence the interval is, [0, 1.442]

^{0}

A= [ 3X- X^{2.08}/2.08]^{1.442}

^{ 0}

A= [4.326- 1.029]-[0-0]

A= 5.586 sq. units

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