Answer to Question #102793 in Civil and Environmental Engineering for John

Question #102793
A 2 tonnes car is towed by a 2.5 tonnes truck which moves off from rest and reaches a
speed of 2m/s before the tow-rope tightens on the stationary car. The rope then stretches
taking up the strain for 0.15 seconds.Find:
(a) the common speed when the rope ceases to stretch
(b) the average impulsive force in the rope.(Neglect resistance and the effect of the truck’s
propelling force during the stretching period
1
Expert's answer
2020-02-13T06:17:42-0500

a)force=mass*acceleration

=(2.5*1000+2*1000)*2m/s

F=9000N

Which is Rt =9000N

at=Rt/m=9000N/2000

=4.5m/s

now the common speed is 4.5m/s

b)impulse force =force*time

=9000N*0.15second

=1350N.S



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