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Answer to Question #94387 in Chemical Engineering for Nduduzo

Question #94387
The value of the second ionisation energy of calcium is 1150KJ.mol-1 Which equation correctly represent this statement? A. Ca^+(g) = Ca^2+(g) + e^- Delta = +1150KJ.mol-1 B. Ca(g) = Ca^2+(g) + 2^e^- Delta = +1150KJ.mol-1 C. Ca^+(g) = Ca^2+(g) + e^- Delta = -1150KJ.mol-1 D. Ca(g) = Ca^2+(g) + 2e^- Delta = -1150KJ.mol-1
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