Answer to Question #94387 in Chemical Engineering for Nduduzo

Question #94387
The value of the second ionisation energy of calcium is 1150KJ.mol-1
Which equation correctly represent this statement?
A. Ca^+(g) = Ca^2+(g) + e^-
Delta = +1150KJ.mol-1
B. Ca(g) = Ca^2+(g) + 2^e^-
Delta = +1150KJ.mol-1
C. Ca^+(g) = Ca^2+(g) + e^-
Delta = -1150KJ.mol-1
D. Ca(g) = Ca^2+(g) + 2e^-
Delta = -1150KJ.mol-1
1
Expert's answer
2019-09-23T03:49:28-0400

(A) Ca+(g)=Ca2+(g) + e-

Delta= +1150 kJ/mole


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