Answer to Question #247824 in Chemical Engineering for Lee

Question

Brackish water is desalinated by evaporation for irrigation purposes. If the feed water has 800.96 ppm of salt, and if the product has to contain 0.0034 % salts as illustrated in Fig 1, what fraction of the feed water should bypass the evaporator?

Answer 1

feed water = 800.96 ppm

product water = 0.0034% = 34 ppm

$800.96 ×( 1-x)= 34 × x\\ 800.96- 800.96x = 34x\\ 800.96 = 834.96x\\ x = 800.96/834.96 = 0.959$

part needed to bypass = $1-0.959$ =

$0.041$