Answer to Question #243747 in Chemical Engineering for Lokika

Question

The radius of convergence of the Taylor series expansion of the functiorf(z)=3z+5/(z+1)^{2} (z-2) about z=1 is.

A)1. B)2. C)3.

D) Infinity

Answer 1

The radius of convergence of the Taylor series expansion of the function $f(z)=3z+5/(z+1)^{2} (z-2)$ about z=1 is infinity.
so the option D is correct