Answer to Question #239556 in Chemical Engineering for nikki

Question

A car manufacturer claims that its car can accelerate from rest to 28 m/s in 14 seconds. Find the average acceleration and the distance the car has traveled while in the process of stopping

Answer 1

Average Acceleration

$a=\frac{V_f-V_i}{t}$

$=(28-0)/14=2m/s^2$

distance=?

$d=st$

$d=28m/s \times14s$

$d=392m$