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# Answer to Question #236266 in Chemical Engineering for Potti

Question #236266

8)Solve (D²+3DD'+2D'^2)z=x cos y+e^x+y, Where D=∂\∂x and D'=∂\∂y.

Explain the problem with step by step process?

1
2021-09-20T02:53:11-0400

The degree of the differential equation is the power of the highest order derivative, where the original equation is represented in the form of a polynomial equation in derivatives such as y’,y”, y”’, and so on.

"(d2y\/dx2)+ 2 (dy\/dx)+y = 0" , so the degree of this equation here is 1. See some more examples here:

• "dy\/dx + 1 = 0," degree is 1
• "(y\u201d\u2019)^3 + 3y\u201d + 6y\u2019 \u2013 12 = 0," degree is 3
• "(dy\/dx) + cos(dy\/dx) = 0;" it is not a polynomial equation in y′ and the degree of such a differential equation can not be defined.

Note:

Order and degree (if defined) of a differential equation are always positive integers.

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