Question #231019

2)What is the steady state approximation?

Expert's answer

Let us consider consecutive reaction means the reaction in series. In these reaction intermediate is formed.

A------>I------>C

A is the reactant

I is the Intermediate

C is the product

dC/dt=K_{2}l

dI/dt=0 steady state approximation

It means the concentration of intermediate product with respect to time is constant

Overall rate law

dI/dt = K_{1}A-K_{2}I

At steady state approximation

0=K_{1}A-K_{2}I

K_{1}A=K_{2}I. ---------(1)

From above equation it is clear that the rate of consumption of intermediate is equal to the rate of formation of intemediate

I=K_{1}A/K_{2}

We also use steady state approximation because the rate law expression is in terms of reactants not in terms of intermediate.

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