Answer to Question #230837 in Chemical Engineering for mya

Question #230837

A petrochemical plant in Jurong Island produces formaldehyde (CH2O) industrially by the catalytic oxidation of methanol (CH3OH). The following is the chemical reaction: CH3OH + ½O2 → CH2O + H2O --- (Equation 1) Unfortunately, a significant portion of the formaldehyde will react with oxygen to produce CO and H2O. The following is the side reaction: CH2O + ½O2 → CO + H2O --- (Equation 2) Assume twice the stoichiometric amount of air needed for oxidation (include Equation (1) and Equation (2)) is fed to the reactor. The conversion of methanol is 90% in the reactor. The outlet stream of the reactor was analysed and found to be 150 kg/hr of formaldehyde, 30 kg/hr of CO and other components.

(i) Determine the mass flowrate (kg/hr) of Stream A. ( 4 marks ) (ii) Determine the molar flowrate (kg-moles/hr) of Stream B. ( 4 marks ) (iii) Determine the mass flowrate (kg/hr) of water in the outlet stream. ( 4 marks ) (iv) Determine the molar composition in the outlet stream. ( 5 marks )

Expert's answer

Mole of formaldehyde in the outlet

Part (i)

To find the the mass flow-rate (kg/hr) of Stream A we can denote it as x

Part (ii)

To determine the molar flow rate (kg-moles/hr) of Stream B we can denote it as y

Part (iii)

Mass flow rate of water =

Mass flow rate =

Mass flow rate of water =

Part (iv)

The molar composition of CO =

The molar composition of H2O =

The molar composition of CH3OH =

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