Answer to Question #226457 in Chemical Engineering for Thanatos

Question #226457
The indicating liquid in a manometer is water (sg = 0.997) and the other liquid is benzene (sg = 0.879). The two liquids are essentially insoluble in each other.

If the manometer reading is 13.8 cm of water, what is the pressure difference in Pa?
1
Expert's answer
2021-08-17T04:27:02-0400

"\\begin{aligned}\n\u2206P &= \\rho_wh_wg_w - \\rho_mh_mg_m\\\\\n &= g(\\rho_wh_w-\\rho_mh_m)\\\\\n&= g\\rho_{H_2O}(sg_w-sg_b)\u2206h\n\\\\&= 9.8\u00d7 1000\u00d7(0.997-0.879)(13.8\u00d710^{-2})\\\\\n&= 159.6\\ Pa\n\\end{aligned}\\\\"

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