Answer to Question #225913 in Chemical Engineering for Lokika

Question #225913

Solution of (D³ - 2D² - 3D)y = 0


A) y = C1.₁e^{x} + C₂е^{-x }+ С3.e^{3x} B) y = C1e^x + C₂е^{-x} + С3.e^{-3x}


C) y = C1+C₂е^{-x} + С3.e^{3x}


D) y = C₁+C₂е^{-x} + С3e^{-3x}


1
Expert's answer
2021-08-18T09:51:01-0400


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