Answer to Question #224860 in Chemical Engineering for Lokika

Question

Evaluate the line integral of →{v}=xyi+y^{2}zj+e^{2z}k over the curve C whose parametric representation is given by x=t^{2},y=2t,z=t,0<t<1.

Answer 1

Given that

${v}=xyi+y^{2}zj+e^{2z}k\\ x=t^{2},y=2t,z=t,0<t<1.\\$

Now the line integral is

$\int_C Vdr\\ {v(t)}=xyi+y^{2}zj+e^{2z}k\\ \space \space \space \space \space \space \space = 2t^3i+4t^3j +e^{2t}k\\ dr = (2t,2,1)\\ {v(t)}dr=2t(2t^3)+2(4t^3)+1(e^{2t})\\ \space \space \space \space \space \space \space \space \space \space \space \space = 4t^4+8t^3+e^{2t}\\ \therefore \int_C V.dr = \int_0^1(4t^4+8t^3+e^{2t})dt\\ (\frac{4}{5}t^5+\frac{8}{4}t^4+\frac{1}{2}e^{2t})_0^1\\ \frac{23}{10}+\frac{1}{2}e^2$