Answer to Question #223819 in Chemical Engineering for Lokika

Question

limz→0 z^{2}-sinz/z

Answer 1

$\lim _{z\to \:0}\left(z^2-\frac{\sin \left(z\right)}{z}\right)\\ \lim _{x\to a}\left[f\left(x\right)\pm g\left(x\right)\right]=\lim _{x\to a}f\left(x\right)\pm \lim _{x\to a}g\left(x\right)\\ With\:the\:exception\:of\:indeterminate\:form\\ =\lim _{z\to \:0}\left(z^2\right)-\lim _{z\to \:0}\left(\frac{\sin \left(z\right)}{z}\right)\\ =0-1\\ =-1$