Answer to Question #210619 in Chemical Engineering for amit

Question #210619

2 tonnes of galena is to be reduced to fine powder by passing through a crusher and a grinder in succession, drawing powder from the same drive. Screen analysis of feed, product from crusher and product from grinder indicated surface areas of 5, 115 and 1000 m²/kg respectively. If the power required by the drive to run the crusher driver assembly is 20 KW and efficiency of crusher is 20%, find the efficiency of grinder. Rittinger's number for galena is 100 m²/kj


1
Expert's answer
2021-06-28T03:18:02-0400

20kW = ∆A (115/5)

x kW = ∆A (1000/115)


x = \dfrac{1000}{115}×20×\dfrac{5}{115}


x = 7.56kW

7.56W = 20%

\therefore  100% = 37.8kW


2 tonnes = 2000kg

2000kg ×\dfrac{1000}{115}m²/kg= 17391m²


Rate of grinder reduction = {37.8×}{100} =3780m²/s


\%E =\dfrac{3780}{17391} ×100\%= 21.74\%

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

Comments

No comments. Be the first!

Leave a comment

Ask Your question

LATEST TUTORIALS
New on Blog
APPROVED BY CLIENTS