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# Answer to Question #208093 in Chemical Engineering for 1234

Question #208093

2 tonnes of galena is to be reduced to fine powder by passing through a crusher and a grinder in succession, drawing powder from the same drive. Screen analysis of feed, product from crusher and product from grinder indicated surface areas of 5, 115 and 1000 m²/kg respectively. If the power required by the drive to run the crusher driver assembly is 20 KW and efficiency of crusher is 20%, find the efficiency of grinder. Rittinger's number for galena is 100 m²/kj

1
2021-06-18T07:55:00-0400

20kW = ∆A (115/5)

x kW = ∆A (1000/115)

x = "\\dfrac{1000}{115}\u00d720\u00d7\\dfrac{5}{115}"

x = 7.56kW

7.56W = 20%

"\\therefore" 100% = 37.8kW

2 tonnes = 2000kg

"2000kg \u00d7\\dfrac{1000}{115}m\u00b2\/kg= 17391m\u00b2"

Rate of grinder reduction = "{37.8\u00d7}{100} =3780m\u00b2\/s"

"\\%E =\\dfrac{3780}{17391} \u00d7100\\%= 21.74\\%"

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