# Answer to Question #180888 in Chemical Engineering for Abaya felix

Question #180888

CPT 307 ASSIGNMENT

The Figure below shows a cross section through an insulated heating pipe which is made from steel (k = 45 W / m K) with an inner radius of 150 mm and an outer radius of 155 mm. The pipe is coated with 100 mm thickness of insulation having a thermal conductivity of k = 0.06 W / m K. Air at Ti = 60°C flows through the pipe and the convective heat transfer coefficient from the air to the inside of the pipe has a value of hi = 35 W / m2 K. The outside surface of the pipe is surrounded by air which is at 15°C and the convective heat transfer coefficient on this surface has a value of ho = 10 W / m2 K. Calculate the heat loss through 50 m of this pipe.

1
2021-04-14T07:43:16-0400 The insulation radius which resistance to heat flow is minimum, and consequently heat flow rate is maximum is called “critical radius”.

The critical radius of insulation for a cylindrical body:

"{r_{cylinder}} = \\frac{k}{h}"

where, k = conductivity of insulation, h = convective heat transfer coefficient of outer body.

"k = 0.06 W\/mK, \\quad h = 10 W\/m^2K"K

"\\begin{aligned} {r_c} &= \\dfrac{k_{insulation}}{h_{outside}} \\\\ \\\\ &= \\dfrac{0.06}{10} \\\\ \\\\ &= 0.006m\\\\ &= 6mm \\end{aligned}"

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