To answer the question, we have to compare the trial product, Q , with K
If Q = K the system is at equilibrium
If Q < K , the reaction will shift to the right and produce more product.
If Q > K, the reaction will shift to the left.
Q is a trial product: [PCl5]/[Cl2][PCl3] = 0.00500/0.0240(0.0420) = 4.96
Since 4.96 is greater than 0.18 the reaction proceeds to the left. By shifting left, the concentration of PCl5 will decrease and Cl2 and PCl3 will grow.
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