Answer to Question #90968 in Chemistry for kenya

Question

A 60g sample of iron reacts with 26g
of oxygen to form how many grams of iron oxide?
Express your answer using two significant figures.

Answer 1

4Fe + 3O₂ --> 2Fe₂O₃

n=m/M

n(Fe)=60/56=1.07 mol

n(O₂)=26/32=0.81 mol

n(Fe)/4 : n(O₂)/3 = 0.2678 : 0.2708 --> Fe is a limiting agent

n(Fe₂O₃)=n(Fe)/2

n(Fe₂O₃)=1.07/2=0.535 mol

M(Fe₂O₃) = 56*2 + 16*3 = 160 g/mol

m(Fe₂O₃)= 0.535*160 = 85.6 g

Answer: 85.6 g