A single force acts on a 4.8 kg particle-like object in such a way that the position of the object as a function of time is given by x = 1.1t - 1.6t2 + 4.1t3, with x in meters and t in seconds. Find the work done on the object by the force from t = 0 to t = 1.5 s.
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2019-06-19T09:28:04-0400
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