Answer to Question #65136 in Chemistry for Leanne

Question

Methanol (CH3OH) is produced commercially by the catalyzed reaction of carbon monoxide and hydrogen:
CO(g)+2H2(g)←−→CH3OH(g).
An equilibrium mixture in a 2.00 −L vessel is found to contain 4.33×10−2 mol CH3OH, 0.180 mol CO, and 0.303 mol H2 at 500 K.
Calculate Kc at this temperature.

Answer 1

Kc = [CH3OH]/[CO][H2]2

[CH3OH] = 7.64·10-2 mol / 1.50 L = 5.09·10-4 M

[CO] = 0.180 mol / 1.50 L = 0.120 M

[H2] = 0.302 mol / 1.50 L = 0.201 M

Kc = (5.09·10-4) / (0.120)(0.201)2 = 0.105