Answer to Question #24951 in Chemistry for jordan

Question

When 14.2 grams of butane are burned, how many grams of oxygen are needed?

Answer 1

The chemical equation for theburning reaction is
2C₄H₁₀ + 13O₂ = 8CO₂ + 10H₂O
n(C₄H₁₀) = m(C₄H₁₀) / M_W(C₄H₁₀) = m(C₄H₁₀) / [4 x M_W(C) + 10 xM_W(H)] = 14.2 / (4 x 12 + 10 x 1) = 0.245 mol
According to chemical equation
n(O₂) = n(C₄H₁₀) : 2 x 13 = 0.245 : 2 x 13 = 1.59 mol
m(O2) = n(O₂) x M_W(O₂) = 1.59 x 32 = 50.88 g
Answer: m(O₂) = 50.88 g