how to prepare 4 ml normal saline solution from 1 percent NaOH
1
Expert's answer
2012-11-19T07:59:27-0500
Saline solution is a solution of sodium chloride (NaCl). NaCl can be prepared from NaOH by reaction with HCl:
NaOH + HCl = NaCl + H2O
4 mL of normal saline content n(NaCl) = V(NaCl) * N(NaCl) = 0.004 L * 1 N = 0.004 mol of NaCl. This quantity of NaCl can be prepared from equal amountof NaOH.
Thus, for preparing 4 mL normal saline solution from 1% NaOH, you should take 16 g of NaOH solution and neutralize it with appropriate amount of HCl (control pH to pH=7). When you finish the neutralization you should evaporate the obtained solution to 4 mL volume.
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