Answer to Question #156034 in Chemistry for ayesha

Question

what concentration of 700.0mL of silver chromate is produced from 0.50mol of silver nitrate?

Answer 1

Solution:

The balanced schematic equation:

CrO₄^2- + 2AgNO₃ → Ag₂CrO₄ + 2NO₃^-

According to the equation above: n(Ag₂CrO₄) = n(AgNO₃)/2

Hence,

Moles of Ag₂CrO₄ = n(Ag₂CrO₄) = 0.50 mol / 2 = 0.25 mol

Molarity of Ag₂CrO₄ = Moles of Ag₂CrO₄ / Volume solution

Thus:

Molarity of Ag₂CrO₄ = 0.25 mol / 0.7 L = 0.357 mol/L = 0.357 M

Molarity of Ag₂CrO₄ = 0.357 M

Answer: 0.357 M is the concentration of silver chromate (Ag₂CrO₄ ).