Answer to Question #156016 in Chemistry for madison

Question

For the reaction: FeCl 3(aq) + 3NaOH(aq) → Fe(OH) 3(s) + 3NaCl(aq) What mass of Fe(OH) 3 can be produced from 135 mL of 0.04 mol/L NaOH? 

Answer 1

Solution:

The balanced chemical equation:

FeCl₃(aq) + 3NaOH(aq) → Fe(OH)₃(s) + 3NaCl(aq)

According to the equation above: n(NaOH)/3 = n(Fe(OH)₃)

Moles of NaOH = Molarity of NaOH × Solution volume

n(NaOH) = Moles of NaOH = 0.04 mol/L × 0.135 L = 0.0054 mol

Moles of Fe(OH)₃ = n(Fe(OH)₃) = n(NaOH)/3

Moles of Fe(OH)₃ = 0.0054 mol / 3 = 0.0018 mol

Moles of Fe(OH)₃ = Mass of Fe(OH)₃ / Molar mass of Fe(OH)₃

The molar mass of Fe(OH)₃ is 106.867 g mol^-1.

Hence,

Mass of Fe(OH)₃ = Moles of Fe(OH)₃ × Molar mass of Fe(OH)₃

Mass of Fe(OH)₃ = 0.0018 mol × 106.867 g mol^-1 = 0.19236 g = 0.19 g

Mass of Fe(OH)₃ = 0.19 g

Answer: 0.19 grams of Fe(OH)₃ can be produced.