Answer to Question #139185 in Chemistry for Chloe Dinkins

Question #139185
When left over a flame a marshmallow is consumed in a combustion reaction. Assuming a marshmallow is made of entirely sucrose, C12H22O11, and after combustion no residual solid remained, the following chemical equation describes this reaction.

C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(g)

Using the chemical equation in Question 1 above, if a second marshmallow was measured and contained 6.94 g of sucrose and is the limiting reactant, what is the theoretical yield, in g, of CO2?
1
Expert's answer
2020-10-19T14:27:46-0400

C12H22O11(s) + 12 O2(g) → 12 CO2(g) + 11 H2O(g)

The mass of carbon dioxide produced in the reaction can be calculated as following:

m(CO2) = m(sucrose) × 12 × Mr(CO2) / Mr(sucrose) = 6.94 g × 12 × 44 g/mol / 342 g/mol = 10.7 g


Answer: 10.7 g

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