6.0 g of cobalt(2) carbonate was added to 40 cm^3 of hydrochloric acid, concentration 2.0 mol/dm3.Calculate the maximum yield of cobalt(2) chloride-6-water and show that the cobalt(2) carbonate was in excess?
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Expert's answer
2012-09-14T09:52:14-0400
n of CoCO3= 6/119=0.05 moles n of HCl= 40*2/1000=0.08 moles using this equation we can see that only 0.04 moles of CoCO3 0.04 0.08 0.04 CoCO3+2HCl=CoCl2+H2O + CO2
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