Answer to Question #99072 in Physical Chemistry for jayasri

Question

the mass of oxygen present in 0.5 mole of P4O10 is

Answer 1

m(P₄O₁₀) = n(P₄O₁₀) • M(P₄O₁₀) = 0,5 mol • (31•4+16•10) g/mol = 0,5 • (136 + 160) = 0,5 • 296 = 148 g

Make a proportion:

Per 148 g of P₄O₁₀ - 296 g/mol

And per X g of Oxygen - 160 g/mol

So, X=148•160/296 = 80 g.

Answer: the mass of oxygen present in 0,5 mol of P₄O₁₀ is 80 grams.