Answer to Question #82693 in Physical Chemistry for Charlotte Joseph

Question #82693
The total alkalinity of a natural water sample is measured by titration and found to contain 1.5 x 10-3 alkalinity equivalents (total alkalinity = [HCO3-] + 2[CO32-] + [OH-] - [H+1]). The pH of this water sample is 10.40. Use this information to calculate answers to the following questions. Use the equations given below.
a. What percent of the carbonate present is in the form of the carbonate ion (CO32-) at pH = 10.40?
b. What is the molar concentration of carbonate ion (CO32-) in this sample?
c. What would be the concentration of calcium ion if this sample is in equilibrium with solid calcium carbonate.
1
Expert's answer
2018-11-07T06:16:50-0500
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