Answer to Question #7466 in Physical Chemistry for Crystal
128 grams of oxygen reacted. After the combustion of an unknown hydrocarbon, the total pressure of a 18.91-L container is 7.3347 atm at 22.7 degrees celsius. What is the hydrocarbon?
PV=nRT n1=PV/RT n=7.3347*101.3*18.91/8.31*295.7=5.718 moles n2=128/32=4 CO2 is gas at this condition CxHy + (x+y/4)O2=xCO2 +y/2H2O as we see,coefficient near O2 (x+y/4) must be biger that near CO2 x.Coefficients are proportional to the amounts (n2 must be > than n1),so this task can't be solved.