Question #7103

Sandra has 500g of water boiling at 99 celsius (C), her recipe calls for water to be at 78C, ice is at 0C, how much ice must she add to cool down the water?

Expert's answer

C1 for water =4200 J/kg*K

C2 for ice

=2100

m1=500

t1=99

t2=0

L=335

kJ/kg

m1*c1*(t-t1)=m2*L+m2*c1*(t-t2)

m2=66.5

C2 for ice

=2100

m1=500

t1=99

t2=0

L=335

kJ/kg

m1*c1*(t-t1)=m2*L+m2*c1*(t-t2)

m2=66.5

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