# Answer to Question #6679 in Physical Chemistry for Sulochana

Question #6679

the ionization energy of hydrogen atom is 13.6 eV. The kinetic energy of the electron in hydrogen atom is a) 13.6 ev B0 31.6 eV C) 6.8 eV D0 21.7 eV

Expert's answer

The energy of the electron in the nth Bohr orbit is

En=-Z2*Rch/n2

Given, ionization energy of hydrogen atom = Rch=13.6 eV.

Therefore, En=-(13.6 eV)*Z2/n2.

Kinetic& energy of the electron in the first Bohr orbit is E1=-13.6 eV.

The answer is a)13.6 eV

En=-Z2*Rch/n2

Given, ionization energy of hydrogen atom = Rch=13.6 eV.

Therefore, En=-(13.6 eV)*Z2/n2.

Kinetic& energy of the electron in the first Bohr orbit is E1=-13.6 eV.

The answer is a)13.6 eV

Need a fast expert's response?

Submit orderand get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

## Comments

## Leave a comment