Answer to Question #6679 in Physical Chemistry for Sulochana

Question

the ionization energy of hydrogen atom is 13.6 eV. The kinetic energy of the electron in hydrogen atom is a) 13.6 ev B0 31.6 eV C) 6.8 eV D0 21.7 eV

Answer 1

The energy of the electron in the nth Bohr orbit is
En=-Z2*Rch/n2
Given, ionization energy of hydrogen atom = Rch=13.6 eV.
Therefore, En=-(13.6 eV)*Z2/n2.
Kinetic& energy of the electron in the first Bohr orbit is E1=-13.6 eV.
The answer is a)13.6 eV