Question #6377

A gas sample occupies 3.25 liters at 24.5 degrees Celsius and 1825 mm hg. Determine the temperature at which the gas will occupy 4250 ml at 1.50 atm

Expert's answer

V1=3,25 L V2=4250 ml=4,25

L

t1=24,5 C (273 +24,5)=297,5 K P2=1,5 atm =151,95 kPa

P=1825

mm hg =243,25 kPa t2=

???

P1V1=nRT1

P2V2=nRT2

nR=const

P1*V1/T1=P2*V2/T2

T2=P2*V2*T1/P1*V1

T2=(151,95*4,25*297,5)/243,25*3,23=242,8

t2=242,8

L

t1=24,5 C (273 +24,5)=297,5 K P2=1,5 atm =151,95 kPa

P=1825

mm hg =243,25 kPa t2=

???

P1V1=nRT1

P2V2=nRT2

nR=const

P1*V1/T1=P2*V2/T2

T2=P2*V2*T1/P1*V1

T2=(151,95*4,25*297,5)/243,25*3,23=242,8

t2=242,8

## Comments

## Leave a comment