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Answer to Question #60796 in Physical Chemistry for Amna Iqbal
Question #60796
0.1 mole of PCl5 is heated to 250 C in decimeter cube container .calculate the concentration of chlorine at equilibrium.(Kc at 250 C=0.414)
Expert's answer
PCl5->PCl3+Cl2
Kc= [Cl2][PCl3]/[PCl5]
If CCl2=x,
Kc = 0.414 = x*x/(0.1-x)
X = 0,083257
Answer: Ccl2=0.083 mole
Kc= [Cl2][PCl3]/[PCl5]
If CCl2=x,
Kc = 0.414 = x*x/(0.1-x)
X = 0,083257
Answer: Ccl2=0.083 mole
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