A heat engine absorbs 760 kJ heat from a source at 380K. It rejects (1) 650 kJ, (ii) 560 kJ, (iii) 504 kJ of heat to sink at 280 K. State which of these represent a reversible, an irreversible and an impossible cycle.
Solution According to 2d law of Thermodynamics: deltaT/T1 = A/Q A = deltaT *Q / T1 = 100 * 760 / 380 = 200 kJ. Rejected: 760 – 200 = 560 kJ – ii (reversible cycle). Answer: (ii) 560 kJ - reversible cycle.
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