air contains 20% by volume of oxygen . the volume of air required for the complete combustion of 1litre of methane under the same conditions is ?
Reaction of methane combustion is represented below: CH4 + 3O2 = CO2 + 2H2O So to burn 1litre of methane we need 3 times higher volume of oxygen, what is 3 liters. But in the air is just 20% by volume of oxygen, so we will need V = 3 · 100/20 = 15 litres Answer: 15 liters of air
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