Question #53695

air contains 20% by volume of oxygen . the volume of air required for the complete combustion of 1litre of methane under the same conditions is ?

Expert's answer

Reaction of methane combustion is represented below:

CH4 + 3O2 = CO2 + 2H2O

So to burn 1litre of methane we need 3 times higher volume of oxygen, what is 3 liters.

But in the air is just 20% by volume of oxygen, so we will need

V = 3 · 100/20 = 15 litres

Answer: 15 liters of air

CH4 + 3O2 = CO2 + 2H2O

So to burn 1litre of methane we need 3 times higher volume of oxygen, what is 3 liters.

But in the air is just 20% by volume of oxygen, so we will need

V = 3 · 100/20 = 15 litres

Answer: 15 liters of air

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