Answer to Question #51828 in Physical Chemistry for Souvik
pOH of the solution is 14-12 = 2.
[OH-] = 10^-2
The number of moles of Ca(OH)2 present in its 100ml solution is: 10^-2*0.1 = 10^-3 moles = 1mole.
Need a fast expert's response?Submit order
and get a quick answer at the best price
for any assignment or question with DETAILED EXPLANATIONS!