Answer to Question #51212 in Physical Chemistry for JUGNU
In a solution 0.200 kg each of water and ethanol are present. Calculate the mole fraction of each
We have solution of water (200 g) and ethanol (200 g).
Let's count moles of water and athanol in solution:
Moles (water) = m(water) / Mr(water) = 200 / 18 = 11 mol.
Moles (ethanol) = m(ethanol) / Mr(ethanol) = 200 / 46 = 4 mol.
Mole fraction = moles(compound) / moles(total)
Mole fraction(water) = moles(water) / moles(total) = 11 / (11+4) = 0.73
Mole fraction(ethanol) = moles(ethanol) / moles(total) = 4 / (11+4) = 0.27