Answer to Question #51212 in Physical Chemistry for JUGNU

Question #51212
In a solution 0.200 kg each of water and ethanol are present. Calculate the mole fraction of each component.
Expert's answer
We have solution of water (200 g) and ethanol (200 g).

Let's count moles of water and athanol in solution:
Moles (water) = m(water) / Mr(water) = 200 / 18 = 11 mol.
Moles (ethanol) = m(ethanol) / Mr(ethanol) = 200 / 46 = 4 mol.

Mole fraction = moles(compound) / moles(total)
Mole fraction(water) = moles(water) / moles(total) = 11 / (11+4) = 0.73
Mole fraction(ethanol) = moles(ethanol) / moles(total) = 4 / (11+4) = 0.27

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