Answer to Question #50893 in Physical Chemistry for Sumit
AgBr l Ag, (Eo)1/2 = 0.0713 V, Fe3+ l Fe2+, (Eo)1/2 = 0.771 V.
If a1 = 0.34, a2 = 0.1 & a3 = 0.02, then find Q, the reaction Quotient is Q = 0.588. Hence find E for the cell.
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