Question #50814
AT 27 DEGREE TEMPERATURE AND 16.5 ATM PRESSURE NH3 IS IN A CLOSED POT.AT 327 DEGREE TEMPERATURE IT PARTIALLY DISSOCIATES.AT EQUILIBRIUM THE PRESSURE INCREASED AT 45.5 ATM.HOW MUCH NH3 DISSOCIATES TO REACH EQUILIBRIUM.
2NH3=N2+3H2 THE ANS IS 37.8787% BUT HOW?
1
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2015-02-24T09:36:06-0500
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