What is the boiling point of a solution made by adding magnesium chloride, MgCl2, into water? The mole fraction of magnesium chloride in the solution formed is 0.04946. Use the formula of the salt to obtain i.
[Kb = 0.512˚C/m and Tb˚ = 100˚C]
dT=K*m*i dT=T-100 the salt is dissociated according to equation: MgCl2 = Mg(2+) + 2Cl(-) i = 3 dT = 0.512*0.04946*3 = 0.076 the boiling point of the solution is T = 100 + 0.076 = 100.076
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