# Answer to Question #4985 in Physical Chemistry for jermain

Question #4985
a chemist wanted to make 100 grams of SO2. She had only 12 grams of sulfur and 4 grams of oxygen. Unfortunately, the amounts of reactants were not enough to make the desired product. How much S and O2 would she need in order to obtain the desired grams of product with no leftovers?
S + 02 = SO2 + NO LEFT OVER
1
2011-11-04T10:22:59-0400
The reaction between sulfur and oxygen looks like this:
S + O2 = SO2
As can be concluded from the reaction equation, 1 mol of sulfur reacts with 1 mol of oxygen and generates a 1 mol of SO2.
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So, if we take 12 grams of sulfur and 4 grams of oxygen, only 4 grams of sulfur will react. Thus, only 8 grams of SO2 can be obtained in such way. Other 8 g of sulfur (12 &ndash; 4 = 8) will remain in the reaction mix.
Since molecular weights of sulfur (S: 321 = 32 g/mol) and oxygen (O2: 162 = 32 g/mol) is equal, the same number of grams of S and O2 contains the same quantity of molecules. So, it&rsquo;s easy to see that for synthesis of 100 grams of SO2 we should take 50 grams of sulfur and 50 grams of oxygen (1:1).

Right answer: to obtain the desired 100 grams of SO2, she should take 50 grams of sulfur and 50 grams of oxygen.

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