Answer to Question #4903 in Physical Chemistry for Davis G
Carbon – 12.011 a. m. u.
Oxygen – 15.999 a. m. u.
Hydrogen – 1.0079 a. m. u.
Firstly we must determine the total mass of atoms of each element of compound.
The total mass of atoms of Carbon will be calculated in the following way:
42.1%/100%*342.30008 a. m. u. = 144.108 a. m. u.
So, the number of atoms of Carbon will be:
144.108/12.011 = 12
For Oxygen this calculation will have the following view:
51.4%/100%* 342.30008 / 15.999 = 11.
Finaly for Hydrogen:
6.5%/100%* 342.30008 / 1.0079 = 22.
So, the empirical formula of this compound is C12H22O11.
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