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Answer to Question #43217 in Physical Chemistry for Sumit

Question #43217
Justify - H*(CO2) = Delta_f H*(CO2) [*means zero in superscript and _f means f in subscript]

where, H* is standard enthalpy and Delta_f H* means standard enthalpy change of formation.
Expert's answer
C + O2 --> CO2

Delta_f H*(CO2) = H*(CO2) - [H*(C) + H*(O2)]
The standard enthalpy of elementary substance is zero:
H*(C) = H*(O2) = 0
Delta_f H*(CO2) = H*(CO2) - [H*(C) + H*(O2)] = H*(CO2) - [0 + 0] = H*(CO2)

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Assignment Expert
11.06.14, 17:49

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11.06.14, 15:55

Thank you a lot........

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