4Al + 3O2 ---> 2 Al2O3
If 0.54 mole of Al reacts with 0.54 mole of O2, as above, how many moles of Al2O3 could form?
a) 0.27 mole
b) 0.36 mole
c) 0.81 mole
d) 1.08 mole

The limiting reactant in this reaction is aluminium, so your calculations should be based on the amount of aluminium. The oxygen is in excess, therefore the calculations based on its amount will lead to the overestimated value.

manoj

05.06.14, 19:46

respected sir, my answer is not coming correct by this method .can we use this method to solve this question? limiting reagent is oxygen, 0.54mole of O2=17.28g, 96g of oxygen produce=204g of Al2O3, 17.28gproduce=36.72g of Al2O3 36.72g of Al2O3=0.36mole of Al2O3

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Assignment Expert06.06.14, 14:40The limiting reactant in this reaction is aluminium, so your calculations should be based on the amount of aluminium. The oxygen is in excess, therefore the calculations based on its amount will lead to the overestimated value.

manoj05.06.14, 19:46respected sir,

my answer is not coming correct by this method .can we use this method to solve this question?

limiting reagent is oxygen,

0.54mole of O2=17.28g,

96g of oxygen produce=204g of Al2O3,

17.28gproduce=36.72g of Al2O3

36.72g of Al2O3=0.36mole of Al2O3

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