90 068
Assignments Done
99.7%
Successfully Done
In September 2020

# Answer to Question #4007 in Physical Chemistry for Arieta Tekaura

Question #4007
(Chemistry) In a bimolecular reaction A + B &rarr; M, a moles per liter of a substance A and
b moles per liter of a substance B are combined. Under constant temperature the rate of
reaction is
y&prime;= k(a &minus; y)(b &minus; y) (Law of mass action);
that is, y&prime; is proportional to the product of the concentration of the substances that are
reacting, where y(t) is the number of moles per liter which have reacted after time t. Solve
this ODE, assuming a and b not equal
1
2012-03-27T09:51:11-0400
It is second order rate laws because the rate is proportional to the product of two concentrations. By elementary integration of these differential equations Integrated Rate Laws can be obtained
(1/(a-b)) ln((a-Y)/(b-Y))
Where a and b are the initial concentrations of A and B (assuming a not equal to b), and Y is the extent of reaction at time t. Note that the latter can also be written:
(a-x)/(b-x) = (a/b)exp[(a-b)kt].

Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!