Answer to Question #37846 in Physical Chemistry for Sheryn
To ease the calculations, take 1 liter of the solution. Its mass is
m = V*D = 1000*1.10 = 1100 g = 1.10 kg
The mass of sulfuric acid is
m(acid) = m(solution)*w(acid) = 1100*0.15 = 165 g
m(water) = m(solution) - m(acid) = 935 g
The molarity is defined as the number of moles of the solute per liter of the solution.
The molality is defined as the number of moles of the solute per kilogram of the solvent.
To obtain the molarity and molality of the solution we need the number of moles of acid:
n(H2SO4) = m(H2SO4)/M(H2SO4) = 1.684 mol
Hence we can obtain the molarity and molality:
c(H2SO4) = n(H2SO4)/V(solution) = 1.68 mol/l
μ(H2SO4) = n(H2SO4)/m(water) = 1.684/0.935 = 1.80 mol/kg
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