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Answer to Question #34511 in Physical Chemistry for Sriyanka
Question #34511
Integral enthalpy of a solution of KCl when 1 mole of it is dissolved in 20 mole water is +15.90kJ. when 1 mole of it is dissolved in 200 mole water, the change in enthalpy is 15.58kJ. Calculate the enthalpy of hydration.
Expert's answer
The enthalpy of hydration is the change in enthalpy, when a solution containing 1 mole of a solute is diluted from one concentration to another.
dH hyd = 18.58 - 15.90 = 2.68 kJ
dH hyd = 18.58 - 15.90 = 2.68 kJ
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Comments
Dear Syed, we have checked the solution, it is correct.
It is wrong U have taken wrong data in solution
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