Answer to Question #33028 in Physical Chemistry for cedric
x = x(H2O) = 50/18 = 2.78 moles;
moles of urea(CH4N2O) = 3/60 = 0.05 moles;
mole fraction of water in solution = 2.78/(2.78 + 0.05) = 0.98
p'x = 17*0.98 = 16.66
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